(w^2+4w-5)/(w^2-2w+1)

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Solution for (w^2+4w-5)/(w^2-2w+1) equation:


D( w )

w^2-(2*w)+1 = 0

w^2-(2*w)+1 = 0

w^2-(2*w)+1 = 0

w^2-2*w+1 = 0

w^2-2*w+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

w = 2/(1*2)

w = 1 or w = 1

w in (-oo:1) U (1:+oo)

(w^2+4*w-5)/(w^2-(2*w)+1) = 0

(w^2+4*w-5)/(w^2-2*w+1) = 0

w^2+4*w-5 = 0

w^2+4*w-5 = 0

DELTA = 4^2-(-5*1*4)

DELTA = 36

DELTA > 0

w = (36^(1/2)-4)/(1*2) or w = (-36^(1/2)-4)/(1*2)

w = 1 or w = -5

(w+5)*(w-1) = 0

w^2-2*w+1 = 0

w^2-2*w+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

w = 2/(1*2)

w = 1 or w = 1

(w-1)^2 = 0

((w+5)*(w-1))/((w-1)^2) = 0

( w+5 )

w+5 = 0 // - 5

w = -5

( w-1 )

w-1 = 0 // + 1

w = 1

w in { 1}

w = -5

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